b^2-4b+132=0

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Solution for b^2-4b+132=0 equation:


Simplifying
b2 + -4b + 132 = 0

Reorder the terms:
132 + -4b + b2 = 0

Solving
132 + -4b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-132' to each side of the equation.
132 + -4b + -132 + b2 = 0 + -132

Reorder the terms:
132 + -132 + -4b + b2 = 0 + -132

Combine like terms: 132 + -132 = 0
0 + -4b + b2 = 0 + -132
-4b + b2 = 0 + -132

Combine like terms: 0 + -132 = -132
-4b + b2 = -132

The b term is -4b.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4b + 4 + b2 = -132 + 4

Reorder the terms:
4 + -4b + b2 = -132 + 4

Combine like terms: -132 + 4 = -128
4 + -4b + b2 = -128

Factor a perfect square on the left side:
(b + -2)(b + -2) = -128

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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